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4<<1)|(2>>1)<<<Z)|(((x<<2)|0b11&0xFF 3|((x|0)>>6&0x00)(y^(×|0b0101)|0b1< y>>2)&0b10101)>>4<<y&&(f1>5}0x67:x<< x<<2)|0b11&0xFF)>>y|~(4<<1)|(2>>1)<< (y^(x|0b0101)|0b15)|((x|0)>>6&0x00) f1>50x67:x<<1)|((y>>2)&0b10101)>>4<< 4<<1)|(2>>1)<<<Z)|(((x<<2)|0b11&0xFF 3|((x|0)>>6&0x00)|(y^(x|0b0101)|0b1< (y>>2)&0b10101)>>4<<y&&(f1>50x67:x<< x<<2)|0b11&0xFF)>>y|~(4<1)|(2>>1)<< (y^(×0b0101)|0b1<<5)|((x|0)>>6&0x00 f1>50x67:x<<1)|((y>>2)&0b10101)>>4< I know bitwise operators 4<<1)|(2>>1)<<<Z)1(((x<<2)|0b11&0xFF 31((x0)>>680×00)1(v^(×100101)101< c =(v & 0x55555555)+( >>1) & 0x55555555) c = (c & 0x33333333) ((c>> 2)& 0x33333333): c = (c & OxOFOFOFOF) + ((c > 4) & OxOFOFOFOF); Show me bitcount c = (c & Ox00FFO0FF) + ((c >> 8) & Ox00FFOOFF) c = (c & 0x0000FFFF) + ((c >> 16)& 0x0000FFFF); He is the one
